Quote:
Originally Posted by Shock Theta
- A x B x C = 72
- There are twelve possible solutions.
- A + B + C = X
- There are two possible solutions. The second man knows his flight number, and cannot answer the question. Thus, as there are only two cases of the sum of the age of each of the three children giving the same result - 14 - this is both the flight number and the two possible age sets.
- One child is younger than the other two.
- There is one possible solution.
I assumed the ages had to be whole numbers, otherwise this is unsolvable.
I'll take sterling. Thanks. |
Yeah, that was the exact approach I was taking, except I got caught up in the whole situation I'm sure you've seen.. so I couldn't get to the math detailing part you did in excel...sadfaic...
this is as far as I had written:
Quote:
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Originally Posted by SargeantSarcasm
The factors of 72 are as follows: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72
So. If he said that they are multiplying the ages of the sons, and that equals 72, then the youngest, David, cannot be 0 years old, or still in the womb. Which was proven above thereby voiding this entire statement, its just to get it out of my head.
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Woe is me.